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The total number of `alpha and beta` particles emitted in the nuclear reaction `._(92)^(238)U rarr ._(82)^(214)Pb` is

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Correct Answer - 8
`._(92)^(238)U rarr ._(82)^(214)Pb + 6(._(2)^(4)He) + 2 (._(-1)e^(0))`
`alpha = 6, beta = 2`
Total = 8

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