Question

What will be the pH value of 0.05 M `Ba(OH)_(2)` solution
A. 12
B. 13
C. 1
D. 12.96

Answer 1

Correct Answer - B
`{:(Ba(OH)_(2),rarr,Ba^(+2)+,2OH^(-)),(,,0.05 M,2 xx 0.5 M):}`
`pOH = log.(1)/([OH^(-)]) = log.(1)/(0.1) = 1`
`pH = pOH = 14 , pH + 1 = 14, pH = 14 -1 = 13`.