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The dissociation constant of two acids `HA_(1)` and `HA_(2)` are `3.14 xx 10^(-4)` and `1.96 xx 10^(-5)` respectively. The relative strength of the acids will be approximately
A. `1:4`
B. `4:1`
C. `1:16`
D. `16:1`

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Correct Answer - B
`(alpha_(1))/(alpha_(2)) = sqrt((K_(a_(1)))/(K_(a_(2))) )= sqrt((3.14 xx 10^(-4))/(1.6 xx 10^(-5))) = 4:1`.

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