Question

Standard entropy of `X_(2),Y_(2)` and `XY_(3)` are 60, 40 and 50 `JK^(-1)mol^(-1)`, respectively. For the reaction, `(1)/(2)X_(2)+(3)/(2)Y_(2)rarrXY_(3),DeltaH=-30kJ` to be at equilibrium, the temperature will be
A. 500 K
B. 750 K
C. 1000 K
D. 1250 K

Answer 1

Correct Answer - B
`(1)/(2)X_(2)+(3)/(2)Y_(2)rarrXY_(3)`
`DeltaS=50-((60)/(2)+(3)/(2)xx40)=50-(30+60)=-40J//k, mol`
at equilibrium `DeltaG=0`
`DeltaH=TDeltaS, T=(DeltaH)/(DeltaS)=(-30xx10^(3))/(-40)=750 K`