Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
191 views
in Chemistry by (93.2k points)
closed by
When 400 ml of 2.0 N solution of a weak acid is neutralized by a dilute aqueous solution of sodium hydroxide under standard conditions, 4.4 kJ amount of heat is liberated. Therefore, the standard enthalpy of neutralization of this weak acid in kJ `eq^(-1)` is
A. `-11`
B. `-44`
C. `-55`
D. `-22`

1 Answer

0 votes
by (91.8k points)
selected by
 
Best answer
Correct Answer - C
No. of equivalents of weak acid `0.4xx0.2`=0.08
So, amount of heat liberated per equivalent
`-(4.4)/(0.08)=-55 kJ`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...