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For the reaction `A(g)+2B(g)rarr2C(g)+3D(g)`, the value of `DeltaE` at `27^(@)C` is 19.0 kcal. The value of `DeltaH` for the reaction would be `(R=2.0 cal K^(-1) mol^(-1))`
A. 20.8 kcal
B. 19.8 kcal
C. 18.8 kcal
D. 20.2 kcal

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Correct Answer - D
Use `DeltaH=DeltaE+DeltanRT`
`DeltaH=19+2xx2xx10^(-3)xx300=20.2 kcal , Deltan=2`.

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