Question

For a first order reaction `A to ` product the rate of reaction at [A] = `0.2 mol l^(-1)` is `1.0 xx 10^(-2) "min"^(-1)` . The half life period for the reaction is
A. 832 s
B. 440 s
C. 416 s
D. 13.86 s

Answer 1

Correct Answer - a
r = k [reactant] `" " therefore k = (1.0 xx 10^(-2))/(0.2) = 0.05`
`t_(1//2) = (0.693)/(0.05)` = 13.86 mint = `13.86 xx 60 = 831.6` sec .