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The line `2y=3x+12` cuts the parabola `4y=3x^(2)`.
What ishte eccentricity of rectangular hyper bola ?
A. `sqrt2`
B. `sqrt3`
C. `sqrt5`
D. `sqrt6`

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Best answer
Correct Answer - A
Here, `b^(2)=a^(2)(e^(2)-1)`
For rectangular hyperbola : a = b
`rArrb^(2)=b^(2)(e^(2)-1)`
`rArr" "e^(2)-1=1`
`rArr" "e^(2)=2rArre=+-sqrt2`
`"For hyperbola, "egt1`.
Hence, `e=sqrt2`

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