Correct Answer - A
Magnetic moment `( mu)= sqrt(n(n+2)) B.M.`
(a) `Co^(3+) rarr 1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(0)3d^(6)`
`mu= sqrt(4(4+2))= sqrt(24)B.M.`
(b) ` Cr^(+3) rarr 1 s^(2) 2s^(2)2p^(6)3s^(2)3p^(6) 4s^(0)3d^(3)`
`mu = sqrt(3(3+2))= sqrt(15)B.M.`
(c ) `Fe^(3+)rarr 1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(0)3d^(5)`
`mu= sqrt(5(5+2))= sqrt(35)B.M. `
(d) `Ni^(+2) rarr 1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(0)3d^(8)`
`mu = sqrt(2(2+2))= sqrt(8) B.M.`