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200 ml 0.6 N `H_(2)SO_(4)` and 100 ml of 0.3 N HCl are mixed together. Acidic normality of the resultant solution is
A. 0.5 N
B. 0.9 N
C. 0.3 N
D. 0.6 N

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Correct Answer - A
`N_(1)V_(1)+N_(2)V_(2)=N_(3)V_(3)`
`200xx0.6+100xx0.3=N_(3)V_(3) and V_(3)=V_(2)+V_(1)=300ml`
`thereforeN_(3)=0.5N`

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