Question

0.1914g of an organic acid is dissolved in approx. 20 ml of water. 25 ml of 0.12 N NaOH required for the complete neutralization of the acid solution. The equivalent weight of the acid is
A. 65
B. 64
C. 63.8
D. 62.5

Answer 1

Correct Answer - C
Volume`=25ml=(25)/(1000)`litre
normality`=(wt)/(eq.wtxxvolume)implies0.12=(0.1914xx1000)/(Exx25)`
eq.wt.`=(0.1914xx1000)/(0.12xx25)=63.8`.