Question

The equivalent weight of `Zn(OH)_(2)` is the following reaction is equal to its, `[Zn(OH)_(2)to(NO_(3))toZn(OH)(NO_(3))+H_(2)O]`
A. `("Formula wt.")/(2)`
B. `("Formula wt.")/(1)`
C. `3xx`formula
D. `2xx`formula

Answer 1

Correct Answer - B
Equivalent weight of
`Zn(OH)_(2)=("Molecular weight")/("Acidicty")=(M)/(1)`