Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
283 views
in Chemistry by (94.4k points)
closed by
If 20 ml of 0.25N strong acid and 30 ml of 0.2 N of strong base are mixed, then the resulting solution is
A. 0.25 N basic
B. 0.2 N acidic
C. 0.25 N acidic
D. 0.2 N basic

1 Answer

0 votes
by (93.2k points)
selected by
 
Best answer
Correct Answer - D
`V_(1)=20ml,N_(1)=0.25N,V_(2)=30ml,N_(2)=0.2N`
`thereforeN=(N_(1)V_(1)+N_(2)V_(2))/(V_(1)+V_(2))=(20(0.25)+30(0.2))/(20+30)`
`=(5+6)/(50)=(11)/(50)=0.2N` basic.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...