Correct Answer - B
The formation of n-propyl bromide in presence of peroxide can be explained as follows .
Step-1:peroxide undergo fission to give free radicals `R-O-O-R to 2 -R-overset(.)O`
Step-2:HBr combines with free radical to form bromine free radical `R-overset.O+HBr to R-OH+overset.Br`
Step-3:`Boverset.r` attacks the double bond of the alkene to form a more stable free radical
Step-4:More stable free radical attacks the HBr
`CH_3-dotCH-CH_2-Br+HBr to underset"n-propyl bromide"(CH_3CH_2CH_2Br+Br)`
Step-5: `Bdotr+Bdotr to Br_2`
