Question

How many gm of bromine will react with 21 gm `C_3H_6`
A. 80
B. 160
C. 240
D. 320

Answer 1

Correct Answer - A
`undersetundersetunderset"42 gms""1 mole""Propene"(CH_3-CH)=CH_2+undersetunderset"160 gms""1 mole"(Br_2)to CH_3-underset"1,2-Dibromo propane"(undersetunderset(Br)(|)CH_2-undersetunderset(Br)(|)CH_2)`
`because` 24 gms of propene reacts with 160 gms of bromine
`because` 21 gms of propene `160/42xx21=80` gms