Correct Answer - b
We have , `y=intx^(2)e^(x^(3))dx=(1)/(3)inte^(x^(3))d(x^(3))=(1)/(3)e^(x^(3))+C`.
It passes throught ( 0 , 1) Therefore ,
`1=(1)/(3)+CrArrC=(2)/(3)`
`thereforey=(1)/(3)e^(x^(3))+(2)/(3)`
`rArr3y=e^(x^(3))+2`
` rArr e^(x^(3))=3y=2rArrx^(3)-log_(e)(3y-2)rarrc=root(3)(log_(e)(3y-2))`