Question

What is the range of the function `y=. x^2/(1+x^2)` where `x in RR?`
A. [0,1)
B. [0,1]
C. (0,1)
D. (0,1]

Answer 1

Correct Answer - A
Function `y=(x^(2))/(1+x^(2))x inR`
`{:(x=0,y=0),("x=1, -1",y=(1)/(2)),("x=2, -2",y=(4)/(5)),("x=3, -3",y=(9)/(10)),(.,.),(.,.),(.,.):}`
Clearly `0leylt1`
`impliesy in,[0,1)`
Hence Range of y=[0,1)