Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
100 views
in Mathematics by (92.6k points)
closed by
Evaluate the area bounded by the ellipse `(x^2)/(4)+(y^2)/(9)=1` above the x-axis.

1 Answer

0 votes
by (92.4k points)
selected by
 
Best answer
The given ellispse meets the x-axis at A (-2,0) and B (2,0)
`(x^2)/(4)+(y^2)/(9)=1 y= 3/2 . sqrt(4-x^2)`
`therefore` required area `=underset(-2)overset(2)inty dx=3/2.underset(-2)overset(2)intsqrt(4-x^2)dx`
`= 2xx 3/2 xx underset(0)overset(2)intsqrt(4-x^2)dx`
`=6.underset(0)overset(pi//2)intcos^2 thetad theta` where x=2 sin `theta`
image

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...