Question

How does `Cu_(2)O` act as both oxidant and reductant ?

Answer 1

`Cu^(+)` undergoes disproportionation to form `Cu^(2+)` and Cu.
`2Cu^(+) (aq) to Cu^(2+) (aq) + Cu(s)`
Thus, `Cu^(+)` or `Cu_(2)O` acts both as an oxidant and a reductant