Question

When 9.65 coulomb of electricity is passed through a solution of silver nitrate (Atomic mass of Ag = 108 g `mol^(-1)`, the amount of silver deposited is :
A. 10.8 gm
B. 5.4 gm
C. 16.2 gm
D. 21.2 gm

Answer 1

Correct Answer - A
`W_(Ag)=(E_(Ag)xxQ)/(96500)=(108xx9.65)/(96500)`
`=1.08xx10^(-2)gm=10.8mg`.