Correct Answer - D
`alpha=(wedge_(m))/_(wedge_(oo))`
`wedge_(oo)=400S" "cm^(2)g" "eq^(-1)`
`wedge_(m)=wedge_(oo)xxalpha=400xx(2)/(100)=8`
`wedge_(m)=(kxx1000)/(C)`
`k=(1)/(R)xx`cell constant
`wedge_(m)=(1)/(R)xx`cell constant`xx(1000)/(C)`
`R=("cell constant")/(wedge_(m)xxC)xx1000`
`R=(0.4xx1000)/(8xx0.1)=500ohm`