Question

the number of atoms in 0.1 mole of a triatomic gas is `(N_(A)=6.02xx10^(23) mol^(-1))`
A. `1.800xx10^(22)`
B. `6.026xx10^(22)`
C. `1.806xx10^(23)`
D. `3.600xx10^(23)`

Answer 1

Correct Answer - C
No. of atoms = No. of molecules `xx` atomicity
`0.1 N_(A)xx3=0.1xx6.02xx10^(23)xx3=1.806xx10^(23)`