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The oxidation number of `Cr` in `K_(2)Cr_(2)O_(7)` is
A. `+6`
B. `-7`
C. `+2`
D. `-2`

1 Answer

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Best answer
Correct Answer - A
`K_(2)Cr_(2)O_(7)`
`2+2x-2xx7=0, 2x-14+2=0`
`2x=12, x=12/2=+6`

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