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An aqueous solution of `6.3 g` oxalic acid dihydrate is made up to `250 mL`. The volume of `0.1 N NaOH` required to completely neutralise `10 mL` of this solution is
A. 40 ml.
B. 20 ml.
C. 10 ml.
D. 4 ml.

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Correct Answer - A
Equivalent of `H_(2)C_(2)O_(4).2H_(2)O` in 10m,. = Equivalents of NaOH
`(6.3)/(126//2) xx (10)/(250) = 0.1 xx V` (in litre) V = 0.04 lit = 40 ml

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