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`(sin^2A-sin^2B)/(sinAcosA-sinBcosB)i se q u a lto` `"tan"(A-B)` (b) `"tan"(A+B)` `cot(A-B)` (d) `cot(A+B)`
A. `tan(A-B)`
B. `tan(A+B)`
C. `cot(A-B)`
D. `cot(A+B)`

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Correct Answer - B
`(sin^(2)A-sin^(2)B)/(sinAcosA-sinBcosB)=(2sin(A+B)sin(A-B))/(sin2A-sin2B)`
`=(2sin(A+B)sin(A-B))/(2sin(A-B)cos(A+B))`
`=tan(A+B)`

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