Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.3k views
in Complex Numbers by (94.7k points)
closed by
Find the principal argument of the complex number `sin(6pi)/5+i(1+cos(6pi)/5)dot`

1 Answer

0 votes
by (97.5k points)
selected by
 
Best answer
`Z = sin.(6pi)/(5) + i(1 + cos .(6pi)/(5))`
`= 2 cos.(3pi)/(5)( sin .(3pi)/(5) +i cos.(3pi)/(5))`
`2 cos.(3pi)/(5)(cos((pi)/(2)-(3pi)/(5))+i sin ((pi)/(2)-(3pi)/(5))`
`=2 cos.(3pi)/(5)[cos((-pi)/(10)) + i sin ((-pi)/(10))]`
`=2 cos.(3pi)/(5)[-cos.(pi)/(10) + i sin.(pi)/(10)]`
`= - 2 cos .(3pi)/(5)[ cos(pi-(pi)/(10)) + i sin (pi-(pi)/(10))]`
`=- 2 cos.(3pi)/(5)[cos.(9pi)/(10 )+ i sin.(9pi)/(10)]`
` therefore" " arg(z) = (9pi)/(10), and |z| = - 2 cos .(3pi)/(5)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...