Correct Answer - 1
(1) `omega =e^(i2pi//3)`
`|{:(,z+1,omega,omega^(2)),(,omega,z+omega^(2),1),(,omega^(2),1, z+omega):}|=0`
Applying `(C_(1) to C_(1) + C_(2) + C_(3))`
`|{:(,1,omega,omega^(2)),(,omega,z+omega^(2),1),(,1,1, z+omega):}|=0`
`rArr z^(3) = 0`
z= 0 is only solutions.