Since system of equation is consistent we have
`Delta = |{:(1,,4a,,a),(1,,3b,,b),(1,,2c,,c):}|=0`
`" or " 1(3bc -2bc ) -4a(c-b)+a(2c-3b)=0`
`" or " bc-4ac+4ab+2ac -3ab=0`
" or " bc-2ac+ =2ac`
" or " bc+ ab=2ac`
`" or "(1)/(a)+(1)/(c)=(2)/(b).`
Thus a,b,c are in H.P.