Correct Answer - C
`y=x^(3)-8x+7 and x=f(t)`
`(dy)/(dx)=2 and x = 3" at "t = 0`
`because" "(dy)/(dx)=(dy//dt)/(dx//dt)`
`rArr" "(dx)/(dx)=(dy//dt)/(dy//dx)`
`rArr" "(dx)/(dt=(2)/(3x^(2)-8)`
`rArr" "because " at "t=0, x=3`
`therefore" "(dx)/(dt)("at "t=0)=(2)/(19)`