Correct Answer - 1,2,3,4
`y=f(x)=x^(4)(12log_(e)x-7),xgt0`
`therefore(dy)/(dx)=16x^(3)(3log_(e)x-1)and (d^(2)y)/(dx^(2)) 16x^(2)(9 log_(e)x)`
`(dy)/(dx)=0 rarr x=e^(1//3)`
`At x =-e^(1//3), (d^(2)y)/(dx^(2))gt0 `,hence `x =e^(1//3)` is point of minima
Also for `0ltxlt1,(d^(2)y)/(dx^(2))lt0` and for `xgt1,(d^(2)y)/(dx^(2))gt0`
Hence x =1 is point of inflection and for `ltxlt1` graph is concave downward and for `xgt1` graph is concave upward.