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The unit of permittivity of free space `epsilon_(0)` is:

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The unit of permittivity of free space `epsilon_(0)` is:
A. `"Newton metre"^2// "Coulomb"^2`
B. `"Coulomb"^2 //"Newton metre"^2`
C. `"Coulomb"^2// "(Newton metre)"^2`
D. Coulomb/Newton metre
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Correct Answer - B
`F=(q_1q_2)/(4piepsilon_0r^2) rArr [epsilon_0]=("Coulomb"^2)/("Newton Meter"^2)`
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