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The standard EMF of the cell: `Ni|Ni^(2+)||Cu^(2+)|Cu`, is 0.59 volt. The standard electrode potential (reduction potential) of copper electrode is 0.34 volt. Calculate the standard electrode potential of nickel electrode.

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Correct Answer - `E_(Ni^(2+)//Ni)^(@)=-0.25`volt
`E_(cell)^(@)=E_(Cu^(2+)//Cu)^(@)-E_(Ni^(2+)//Ni)^(@),therefore0.59=0.34-E_(Ni^(2+)//Ni)^(@)` or `E_(Ni^(2+)//Ni)^(@)=0.34-0.59=-0.25V`

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