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`AIF_(3)` is soluble in `HF` only in presence of `KF`. It is due to the formation of
A. `K_(3)[AlF_(3)H_(3)]`
B. `K_(3)[AlF_(6)]`
C. `AlH_(3)`
D. `K[AlF_(3)H]`

1 Answer

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Best answer
Correct Answer - B
KF dissociate to give `F^(-)` and form soluble complex with `AlF_(3)` ltBrgt `AlF_(3)+3KF to K_(3)[AlF_(6)]`

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