Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
226 views
in Chemistry by (97.5k points)
A 0.5% (by weight) solution of `A_(2)B` in solvent C was found to freeze at `-3.25^(@)C`. Calculate the degree of dissociation of `A_(2)B` in solvent C into `A_(2)^(-)` and `B_(2)^(-)`. (Given freezing point of pure C is `-3^(@)C`, molar weight of `A_(2)B` is 60 and `K_(f)` of C is 2 `K^(-1)` "molality"^(-1)`).

Please log in or register to answer this question.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...