Correct Answer - C
Shift = `((mu-1)tD)/d`
At `mu =1, shift=0`
Therefore, intensity at centre is maximum or `I_0`.
As `mu` increases fringes shift upwards as shown in figure.
So, intensity at P first decreases to zero (as Q
reaches at P), then it further increases to `I_0`(as
point R reaches to P).