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`_86A^222rarr_84B^210`. In this reaction, how many `alpha` and `beta` particles are emitted?

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`_86A^222rarr_84B^210`. In this reaction, how many `alpha` and `beta` particles are emitted?
A. `6alpha , 3 beta`
B. `3 alpha , 4 beta`
C. `4 alpha , 3 beta`
D. `3 alpha, 6 beta`
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1 Answer

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Correct Answer - B
Ler `alpha` particles are n and `beta` particles are m. Then,
`86-2n + m = 84 ….(i)`
222 - 4n =210 …(ii)
Solving these two equations, we get n= 3 and
`beta =4.`
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