Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
575 views
in Physics by (92.8k points)
closed by
x-rays are produced in an X-ray tube by electrons asselerated through an electric potential difference fo 50.0 kV. An electron makes three collisions in the target coming to rest and loses half its remaining kinetic energy in each of the first two collisions. Determine the wavelenght of the resulting photons. (Neglecting the recoil of the heavey target atoms).

1 Answer

0 votes
by (92.0k points)
selected by
 
Best answer
Correct Answer - D
`DeltaE_1 = 50% of 50 keV = 23keV`
`:. Lambda_1 = (12375)/(25xx10^3) = 0.495 Å`
= 49.5 pm
`DeltaE_2 = 50% of 25 keV`
=12.5 keV
`:. Lambda_2 = (12375)/(12.5xx10^3) = 0.99 Å`
= 99 pm.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...