Question

In a cold climate water gets frozen causing damage to radiator of a car. Ethylene glycol is used as an anifreezing agent. Calculate the amount of ethylene glycol to be added to `4 kg` of water to prevent it from freezing at `-6^(@)` . (`K_(f)` for water = `1.85 kg mol^(-1)`)

Answer 1

The given values are:
`W_(A)= 2 kg=2xx10^(3) g , Mw_(B)=62 g mol_(-1)`
`K_(f) = 1.8 K m^(-1)`
`DeltaT_(f)=0-(-8)=8^(@)`
Using formula,`W_(B)=(DeltaT_(f)xxW_(A)xxMw_(B))/(K_(f)xx1000)`
`:.W_(B)=(8xx2xx10^(3)xx62)/(1.8xx1000) =551.1 g`
Therefore , the amount of ethylene glycol to be added is `551.11 g`.