Question

A graph is plotted between `E_(cell)` and `log .([Zn^(2+)])/([Cu^(2+)])` . The curve is linear with intercept on `E_(cell)` axis equals to `1.10V`. Calculate `E_(cell)` for the cell.
`Zn(s)||Zn^(2+)(0.1M)||Cu^(2+)(0.01M)|Cu`

Answer 1

Cell reaction is `: Zn+Cu^(2+) rarr Zn^(2+)+Cu`
`E_(cell)=E^(c-)._(cell)-(0.059)/(2) log[(Zn^(2+))/(Cu^(2+))]" "(i)`
`(y=c+mx)" "(ii)`
Equation `(i)` represent a straight line like Eq. `(ii)` .
`:` Intercept `(c)=E^(c-)._(cell)=1.10V`
`:. E_(cell)=1.10V-(0.059)/(2)log .(0.1)/(0.01)`
`=1.10V-(0.059)/(2)log 10`
`=1.10-0.03" "(` tAKE `0.059~~0.06)`
`=1.07V`