Correct Answer - A
` F_(E) = q^(E)` ( force due to electric field)
` F_(B) = evB sin theta = q vB sin 0 = 0`
( force due to magnetic field )
Force due to electric field will make the charged particle released from rest to move in the straight line ( that of eletric field ) . Since the force due to magnetic field is zero , therefore , the charged particle will move in a straight line.