Question

The power of resistor is the maximum power the resistor can safely dissipate without too rise in temperature. The power rating of a `15 kOmega` resistor is `5.0 W`. What is the maximum allowable potential difference across the terminals of the resistor?
(b) A `9.0 kOmega` resistor is to be connected across a `120 V` potential difference. What power rating is required?

Answer 1

Correct Answer - A::B::C
a. `P=V^2/R`
`:. V=sqrt(PR)=sqrt(5xx15xx10^3)=273.8V`
b. `P=V^2/R=((120)^2)/(9xx10^3)=1.6W`