Question

A uniform electric field of magnitude `250 V// m` is directed in the positive x-direction. `A+12muC` charge moves from the origin to the point `(x, y) = (20.0 cm, 5.0 cm).`
(a) What was the change in the potential energy of this charge?
(b) Through what potential difference did the charge move?

Answer 1

Correct Answer - B
a. `/_U=-q(/_V)`
`=-(12xx10^-6)(50)`
`=-6.0xx10^-4J`
`b.` /_V=Ed=E(/_x)`
`=(250)(0.2)`
`=50 V`