Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
85 views
in Physics by (92.0k points)
closed
A `5.80 muF` parallel-plate air capacitor has a plate separation of `5.00 mm` and is charged to a potential difference of `400 V`. Calculate the energy density in the region between the plates, in `J/m^3`
A. `0.113`
B. `0.117`
C. `0.152`
D. none of these

1 Answer

0 votes
by (92.8k points)
 
Best answer
Correct Answer - B
`A=90 cm^(2),d=2 mm`
`E=V/d,V400V`
`u=1/2epsilon_(0)E^(2)=1/2=1/2epsilon_(0)(V/d)^(2)`
`=1/2(8.85x10^(-12))((400)/(2xx10^(-3)))^(2) =0.177 Jm^(-3)`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...