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The potential difference `V_A - V_B` for the circuit shown in fig. is. `-(22//x)V.` find the value of x.
image

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Correct Answer - 9
At junction C: `i_1+i_2 = I,`
where `i_1 = (0-x)/(1), i_2 = (1-x)/(1)`
At D: `4i +i_1 = 0` solve to get `x = (4)/(9)`
image
Now `V_A - i_1 +1 = V_B or V_A or V_B = - (2 + (4)/(9)) = -(22)/(9)V`

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