Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
7.0k views
in Physics by (94.0k points)
closed by
The spring force is given by `F=-kx`, here k is a constant and x is the deformation of spring. The `F-x` graph is
A. image
B. image
C. image
D. image

1 Answer

0 votes
by (93.7k points)
selected by
 
Best answer
Correct Answer - C
given `F=-10x`
The standard equation of straight line is `y=mx+c`
If we compare given equation with the standard equation of Straight line, the intercapt is zero and slope is negative. Hence the graph is passing through origin.
Hence, option (c ) is correct.

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...