Question

Three blocks of masses `m_(1), m_(2)` and `M` are arranged as shown in figure. All the surfaces are fricationless and string is inextensible. Pulleys are light. A constant force `F` is applied on block of mass `m_(1)`. Pulleys and string are light. Part of the string connecting both pulleys is vertical and part of the strings connecting pulleys with masses `m_(1)` and `m_(2)` are horizontal.

`{:((P),"Accleration of mass " m_(1),(1) F/(m_(1))),((Q),"Acceleration of mass" m_(2),(2) F/(m_(1)+m_(2))),((R),"Acceleration of mass M",(3) "zero"),((S), "Tension in the string",(4) (m_(2)F)/(m_(1)+m_(2))):}`
A. `{:(,P,Q,R,S),((A),2,2,3,4):}`
B. `{:(,P,Q,R,S),((B),2,1,3,4):}`
C. `{:(,P,Q,R,S),((C),2,2,4,1):}`
D. `{:(,P,Q,R,S),((D),2,1,3,1):}`

Answer 1

(A) `Q` (b) `Q` (C) `R` (D) `S`

`F-T=m_(1)a`
`F=(m_(1)+m_(2))a`
`because T=m_(2)a`
`rArr a=(F)/(m_(1)+m_(2)) because T=(m_(2)F)/(m_(1)+m_(2)). F_(x)=0,a_(M)=0`