Question

The wavelength of `k_(alpha) ` X- rays produced by an X - rays tube is `0.76 Å` . The atomic number of the anode material of the tube is …….

Answer 1

Correct Answer - b
`(1)/(lambda) = R (z - 1) ^(2) [(1)/(n_(1)^(2)) - (1)/(n_(2)^(2))]`
Since for `K_(alpha), n_(2) = 2 = n_(1) = 1`
`:. (1)/(0.76 xx 10^(-10)) = 1.097 (z - 1) ^(2) [(1)/(1^(2)) - (1)/(2^(2))]`
`implies z - 1 = 40 implies z = 41`