Correct Answer - A::B::D
Methanol is also called carbinol.
a.
b. `Moverset(beta)(e)-underset(Ph)underset(|)overset(alpha)(CH)-OH` (It also contains `(Me-underset(OH)underset(|)(CH)-)` group and gives the iodoform test.)
c. Although `A AE` (acetoacetic easter)
contains `(Me-overset(O)overset(||)(C )-)` group, due to its existence in enolic form
it does not give the iodoform test.
d. `(I_(3)C-CHO)`, this is one of the intermediate products formed in the iodoform reaction, so it gives iodoform test.
So the answers are `(a)`, `(b)`, and `(d)`.
