Correct Answer - a,b
We know,
`N=N_(0) e^(- lambda t)`
Where, `N=number` of decayed nuclei in the sample at time t, `N_(0)` =initial number of nuceli.
Hence, total number of undecayed nuclei `=(N_(0)=N)`
Substituing it in (i), we get
`N_(0)-N=N_(0)(1-e^(-lambda t))`
This shows that the total number of undecayed nuclei decays exponentially with time. Now,
`R= -lambda=(dN)/(dt)" "(R=activiy)`
Hence , activityy `(R) rho` number of undecayed nuclei. Therefore, (a), (b),(c) are correct answers.