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Order of magnitude of density of uranium nucleus is , [m = 1.67 xx 10^(-27 kg]`
A. `10^(20) kg m^(-3)`
B. `10^(17) kg m^(-3)`
C. `10^(14) kg m^(-3)`
D. `10^(11) kg m^(-3)`

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Correct Answer - b
Nuclear density of an atom of mass numner A,
`D=(mass)/(volume)=(A(1.67 xx10^(-27)))/((4)/(3)pi[1.25 xx10^(15) A^(1//3)]^(3))`
`[:. V=4/3 pi R^(3), R=R_0A^(1//3), R_0=1.25 xx10^(-15)]`
`:. D=2xx10^(17) kg m^(-3)`.

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